Question:

The curve, for which the area of the triangle formed by X-axis, the tangent line at any point \(P\) and line \(OP\) is equal to \(a^2\), is given by

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Use intercept form of tangent to relate geometry with differential equations.
Updated On: Apr 16, 2026
  • \(y = x - Cx^2\)
  • \(x = Cy \pm \frac{a^2}{y}\)
  • \(y = Cx \pm \frac{a^2}{x}\)
  • None of these
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The Correct Option is B

Solution and Explanation

Concept: Use tangent form and area of triangle.

Step 1:
Tangent equation.
\[ y - y_1 = m(x - x_1) \] Intercept form gives triangle area.

Step 2:
Area condition.
\[ \frac{1}{2} \times (\text{x-intercept}) \times (\text{y-intercept}) = a^2 \]

Step 3:
Solve differential equation.
Leads to: \[ x = Cy \pm \frac{a^2}{y} \]
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