Step 1: Understanding the Concept
In a pure capacitive circuit, the current leads the applied voltage (emf) by \(\dfrac{\pi}{2}\).
Step 2: Reading the diagrams
Diagram (2) shows the current phasor along the positive direction and the emf phasor perpendicular to it, pointing 90 degrees clockwise from the current. So emf lags the current.
Step 3: Conclusion
This is the case of a capacitor, so diagram (2) is correct.
Final Answer:
Phasor diagram (2) represents a pure capacitor.
\[ \boxed{\text{(B) }\text{(2)}} \]