Step 1: Understanding the Concept
In a pure inductor \(e=L\dfrac{di}{dt}\), so the current lags the applied emf by \(\dfrac{\pi}{2}\).
Step 2: Phasor picture
Phasors rotate anticlockwise, so a phasor that lags is drawn \(90^{\circ}\) clockwise from the emf phasor.
Step 3: Check the figures
Figure A shows the two along the same line in opposite directions and figure C shows them in the same direction.\nFigure D shows the current ahead of the emf, while figure B shows the emf pointing right and the current pointing down, 90 degrees behind.
Final Answer:
Figure B shows the correct phase relation.
\[ \boxed{\text{(B) }\text{B}} \]