Question:

An a. c. source is connected across a pure inductor. Which one of the following figures shows the correct phase relation between the current and e.m.f.?

Show Hint

In a pure inductor the current lags the emf by 90 degrees; phasors rotate anticlockwise.
Updated On: Nov 13, 2026
  • D
  • B
  • A
  • C
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The Correct Option is B

Solution and Explanation

Step 1: Understanding the Concept
In a pure inductor \(e=L\dfrac{di}{dt}\), so the current lags the applied emf by \(\dfrac{\pi}{2}\).

Step 2: Phasor picture
Phasors rotate anticlockwise, so a phasor that lags is drawn \(90^{\circ}\) clockwise from the emf phasor.

Step 3: Check the figures
Figure A shows the two along the same line in opposite directions and figure C shows them in the same direction.\nFigure D shows the current ahead of the emf, while figure B shows the emf pointing right and the current pointing down, 90 degrees behind.

Final Answer:
Figure B shows the correct phase relation. \[ \boxed{\text{(B) }\text{B}} \]
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