Question

The correct order of ionic radius of nitrogen family is:

• A. \(N^{3-}<P^{3-}<As^{3-}<Sb^{3-}<Bi^{3-}\)
• B. \(N^{3-}<P^{3-}<Sb^{3-}\)
• C. \(P^{3-}>As^{3-} = Bi^{3-}\)
• D. \(N^{3-}>Bi^{3-}>Sb^{3-}\)

Hint:

Down the group → more shells → larger ionic radius.

Answer 1

The Correct Option is A

Concept: Ionic radius increases down a group due to the addition of new electron shells.

Step 1: Group 15 elements (Nitrogen family). \[ N,\; P,\; As,\; Sb,\; Bi \]

Step 2: Trend for anions \(M^{3-}\). Down the group, the number of shells increases, so ionic radius increases: \[ N^{3-}<P^{3-}<As^{3-}<Sb^{3-}<Bi^{3-} \]