Step 1: Identify the atomic number of gold.
The element Au is gold.
The atomic number of gold is
\[
Z=79
\]
So, gold has 79 electrons in its neutral atom.
Step 2: Write the expected configuration.
After xenon, the electrons are filled in \(4f\), \(5d\), and \(6s\) orbitals.
The expected configuration may appear as
\[
[Xe]4f^{14}5d^9 6s^2
\]
Step 3: Apply stability of completely filled \(d\)-subshell.
A completely filled \(d^{10}\) subshell is more stable than \(d^9\).
Therefore, one electron from \(6s\) shifts to \(5d\).
Thus,
\[
5d^9 6s^2 \rightarrow 5d^{10}6s^1
\]
Step 4: Write the correct configuration.
Hence, the correct electronic configuration of gold is
\[
[Xe]4f^{14}5d^{10}6s^1
\]
Step 5: Final conclusion.
Therefore,
\[
\boxed{[Xe]4f^{14}5d^{10}6s^1}
\]