Step 1: Set up the family tree.
Two offspring share the same mother but have different, unrelated fathers. Call the offspring X and Y, and the shared mother M. Since the fathers are unrelated to each other and to M, the only path connecting X and Y runs through M.
Step 2: Use the path counting rule for relatedness.
The coefficient of relatedness between two relatives through a common ancestor is found with
\[
r = \left(\frac{1}{2}\right)^{L}
\]
where \(L\) is the number of parent to offspring links (meioses) in the path joining the two relatives through that ancestor.
Step 3: Count the links for half sibs.
The path is X to M to Y. That is one link from M down to X and one link from M down to Y, so \(L = 2\).
Step 4: Apply the formula.
\[
r = \left(\frac{1}{2}\right)^{2} = \frac{1}{4} = 0.25
\]
This matches the standard textbook value for half siblings: full sibs share both parents and get \(r = 0.5\), while half sibs share only one parent and get half that value, \(r = 0.25\).
Final Answer:
The coefficient of relatedness for the two half sib offspring is
\[ \boxed{r = 0.25} \]