Question:

The area of the region R=\(x,y): |x|≤ |y| and x²+y²≤ 1 is

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Convert inequalities to angular regions in polar coordinates.
Updated On: Mar 20, 2026
  • (3π)/(8) sq units
  • (5π)/(8) sq units
  • (π)/(2) sq units
  • (π)/(8) sq unit
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The Correct Option is A

Solution and Explanation

The condition |x|≤ |y| corresponds to angles between θ=(π)/(4) to (3π)/(4) and similarly in all four quadrants. Total angular region: 4((π)/(4))=π Area inside unit circle: (π)/(2π)× π = (3π)/(8)
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