Question:
The minimum value of the function y=x⁴-2x²+1 in the interval [-\frac12,2] is
The minimum value of the function y=x⁴-2x²+1 in the interval [-\frac12,2] is
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Convert to perfect square when possible.
Updated On: Mar 17, 2026
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The Correct Option is A
Solution and Explanation
y=(x²-1)²
Minimum occurs when x²=1 x=±1.
Only x=1 lies in interval.
yᵢₙ=(1-1)²=0
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