Question:

The approximate value of \((1.0002)^{3000}\) is

Show Hint

For small \(x\), \((1+x)^n \approx 1 + nx\).
Updated On: Apr 20, 2026
  • 1.2
  • 1.4
  • 1.6
  • 1.8
Show Solution
collegedunia
Verified By Collegedunia

The Correct Option is C

Solution and Explanation

To find the approximate value of \((1.0002)^{3000}\), we can use the binomial approximation or the exponential function approximation for small values of \(x\).

First, let's use the exponential approximation: 

For small values of \(a\), the expression \((1+a)^n\) can be approximated using:

\((1 + a)^n \approx e^{na}\)

where \(e\) is the base of the natural logarithm, approximately equal to 2.718.

In our problem, \(a = 0.0002\) and \(n = 3000\). So,

\(e^{na} = e^{3000 \times 0.0002} = e^{0.6}\)

Now, calculate \(e^{0.6}\):

\(e^{0.6} \approx 1.6\)

Hence, the approximate value of \((1.0002)^{3000}\) is 1.6.

This matches the correct answer given as 1.6.

To verify, note that this is consistent because the approximation for small values of \(a\) works well here, as \(a = 0.0002\) is very small.

Therefore, the correct answer is: 1.6.

Was this answer helpful?
0
0