To find the approximate value of \((1.0002)^{3000}\), we can use the binomial approximation or the exponential function approximation for small values of \(x\).
First, let's use the exponential approximation:
For small values of \(a\), the expression \((1+a)^n\) can be approximated using:
\((1 + a)^n \approx e^{na}\)
where \(e\) is the base of the natural logarithm, approximately equal to 2.718.
In our problem, \(a = 0.0002\) and \(n = 3000\). So,
\(e^{na} = e^{3000 \times 0.0002} = e^{0.6}\)
Now, calculate \(e^{0.6}\):
\(e^{0.6} \approx 1.6\)
Hence, the approximate value of \((1.0002)^{3000}\) is 1.6.
This matches the correct answer given as 1.6.
To verify, note that this is consistent because the approximation for small values of \(a\) works well here, as \(a = 0.0002\) is very small.
Therefore, the correct answer is: 1.6.