Question

\[ \text { The value of current I in the given circuit is } \]

• A. 7 A
• B. 8 A
• C. 18 A
• D. 10 A

Hint:

Apply the current law to the whole network: the sum of currents entering equals the sum of currents leaving.

Answer 1

The Correct Option is C

Step 1: Understanding the Concept
Kirchhoff's current law says total current entering a network equals total current leaving it.

Step 2: Read the figure
Currents entering the network: 20 A (top left) and 3 A (top right). Currents leaving: 5 A (bottom left) and \(I\) (bottom right). The 15 A is an internal branch current.

Step 3: Apply the law
\(20+3=5+I\).

Step 4: Result
\(I=23-5=18\text{ A}\).

Final Answer:
The current \(I\) is 18 A. \[ \boxed{\text{(C) }\text{18 A}} \]