A liquid is allowed to flow into a tube of truncated cone shape. Identify the correct statement:
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The principle of continuity implies that for an incompressible fluid, as the cross-sectional area decreases, the velocity must increase to maintain constant mass flow.
The speed is high at the wider end and high at the narrow end.
The speed is low at the wider end and high at the narrow end.
The speed is same at both ends in a streamline flow.
The liquid flows with uniform velocity in the tube.
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The Correct Option isB
Solution and Explanation
According to the principle of continuity for an incompressible fluid:
\[
A_1v_1 = A_2v_2,
\]
where \( A \) is the cross-sectional area and \( v \) is the velocity of the fluid.
In a truncated cone, the cross-sectional area at the wider end (\( A_1 \)) is greater than the area at the narrower end (\( A_2 \)). Hence, the velocity at the wider end (\( v_1 \)) is smaller, and the velocity at the narrower end (\( v_2 \)) is higher to conserve mass flow:
\[
v_1<v_2.
\]
Final Answer:
\[
\boxed{\text{The speed is low at the wider end and high at the narrow end.}}
\]