Question:

\(\text{Cosech}^{-1}2+\text{Cosech}^{-1}\left(-\dfrac12\right)=\)

Show Hint

Convert inverse hyperbolic functions into logarithmic form before simplification.
Updated On: Jun 17, 2026
  • \(\log\left(\dfrac{3-\sqrt5}{2}\right)\)
  • \(\log(3-\sqrt5)\)
  • \(\log\left(\dfrac{7+3\sqrt5}{2}\right)\)
  • \(\log\left(\dfrac{4\sqrt5+5}{2}\right)\)
Show Solution
collegedunia
Verified By Collegedunia

The Correct Option is A

Solution and Explanation

Concept: Use the logarithmic form of inverse hyperbolic cosecant.

Step 1: Apply the formula.
\[ \text{cosech}^{-1}x = \log\left(\frac1x+\sqrt{1+\frac1{x^2}}\right) \] For \(x=2\), \[ \text{cosech}^{-1}2 = \log\left(\frac12+\sqrt{1+\frac14}\right) \] \[ = \log\left(\frac12+\frac{\sqrt5}{2}\right) \] \[ = \log\left(\frac{1+\sqrt5}{2}\right) \]

Step 2: Evaluate the second term.
\[ \text{cosech}^{-1}\left(-\frac12\right) = \log\left(-2+\sqrt5\right) \]

Step 3: Add the logarithms.
\[ \log\left(\frac{1+\sqrt5}{2}\right) + \log(-2+\sqrt5) \] \[ = \log\left[ \frac{(1+\sqrt5)(\sqrt5-2)}{2} \right] \] \[ = \log\left(\frac{3-\sqrt5}{2}\right) \] Hence, \[ \boxed{ \log\left(\frac{3-\sqrt5}{2}\right) } \]
Was this answer helpful?
0
0