Question:

Taking into consideration of significant figures, in the conversion relation \(2.0\ \text{m s}^{-2} = X\ \text{km h}^{-2}\), the value of \(X\) is

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Always match significant figures: - Final answer should have same number of significant figures as given data
Updated On: Apr 30, 2026
  • $2.6 \times 10^4$
  • $2.592 \times 10^4$
  • $2 \times 10^4$
  • $2.592 \times 10^5$
  • $2.60 \times 10^5$
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The Correct Option is A

Solution and Explanation

Concept: Unit conversion: \[ 1\ \text{m} = 10^{-3}\ \text{km}, \quad 1\ \text{s} = \frac{1}{3600}\ \text{h} \] Also, significant figures must be preserved in the final answer.

Step 1:
Convert $\text{m s}^{-2}$ to $\text{km h}^{-2}$.
\[ 1\ \text{m s}^{-2} = 10^{-3}\ \text{km} \times (3600)^2\ \text{h}^{-2} \] \[ = 10^{-3} \times 12960000 = 1.296 \times 10^4\ \text{km h}^{-2} \]

Step 2:
Multiply by given value $2.0$.
\[ 2.0 \times 1.296 \times 10^4 = 2.592 \times 10^4 \]

Step 3:
Apply significant figures.
Given $2.0$ has 2 significant figures: \[ 2.592 \times 10^4 \approx 2.6 \times 10^4 \]
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