Question:
Strain vs stress curves for wires \(P, Q, R\). Which is correct?
Strain vs stress curves for wires \(P, Q, R\). Which is correct?
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Greater extension before breaking $\Rightarrow$ higher tensile strength.
Updated On: Apr 23, 2026
- elasticity of P maximum
- elasticity of Q maximum
- tensile strength of R maximum
- None of these
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Verified By Collegedunia
The Correct Option is C
Solution and Explanation
Concept:
Slope of strain vs stress graph = inverse of Young’s modulus.
Step 1: Elasticity
Steeper line $\Rightarrow$ more strain $\Rightarrow$ less elasticity
Step 2: Tensile strength
Maximum extension $\Rightarrow$ strongest wire From graph: \[ R \text{ extends most} \Rightarrow \text{maximum tensile strength} \] Conclusion: \[ {(C)} \]
Step 1: Elasticity
Steeper line $\Rightarrow$ more strain $\Rightarrow$ less elasticity
Step 2: Tensile strength
Maximum extension $\Rightarrow$ strongest wire From graph: \[ R \text{ extends most} \Rightarrow \text{maximum tensile strength} \] Conclusion: \[ {(C)} \]
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