Question:
Simple pendulum lifted upward with acceleration \(a=1m/s^2\). Find ratio \(T_1^2/T_2^2\).
Simple pendulum lifted upward with acceleration \(a=1m/s^2\). Find ratio \(T_1^2/T_2^2\).
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Upward acceleration increases effective gravity.
Updated On: Apr 23, 2026
- 4/5
- 6/5
- 5/6
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The Correct Option is B
Solution and Explanation
Concept:
Effective gravity:
\[
g' = g + a
\]
\[
T \propto \frac{1}{\sqrt{g}}
\Rightarrow T^2 \propto \frac{1}{g}
\]
Step 1: Ratio
\[ \frac{T_1^2}{T_2^2} = \frac{g+a}{g} = \frac{10+1}{10} = \frac{11}{10} \approx \frac{6}{5} \] Conclusion: \(\frac{6}{5}\)
Step 1: Ratio
\[ \frac{T_1^2}{T_2^2} = \frac{g+a}{g} = \frac{10+1}{10} = \frac{11}{10} \approx \frac{6}{5} \] Conclusion: \(\frac{6}{5}\)
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