Question:

Shared setup (chef and ingredients): A chef is preparing a recipe using four ingredients out of six liquids. Two of these ingredients must come from the taste group A, B and C, and the other two must come from the group W, X, Y and Z. Three combinations are never allowed: B with W, C with Y, and Y with Z.

Which of the following must always be true?

I. If C is used, W must be added
II. If Y is used, B must be added
III. If C is not used, W cannot be added

Show Hint

Work out which taste pair each condition forces, then see what that pair locks out.
Updated On: Jul 16, 2026
  • I and II only
  • II and III only
  • I, II and III only
  • II only
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The Correct Option is B

Solution and Explanation

Step 1: Test statement I.
If C is used, the taste pair could be A and C, or B and C. With A and C, nothing blocks W, so W could be added. But with B and C, the B-W rule blocks W outright. Since using C does not always force W in, statement I is not always true.

Step 2: Test statement II.
If Y is used, the C-Y rule removes C from the taste pair. With only A and B left as taste ingredients, both A and B get used, so B is always in the mix whenever Y is used. Statement II is always true.

Step 3: Test statement III.
If C is not used, the taste pair must be A and B, the only pair left from A, B, C once C drops out. Since B is now always used, the B-W rule blocks W every single time. So whenever C is left out, W is always left out too. Statement III is always true.

Final Answer:
Statements II and III always hold, statement I does not. \[ \boxed{\text{II and III only}} \]
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