Question:
\(S_N1\) reactions are generally carried out in which type of solvents?
\(S_N1\) reactions are generally carried out in which type of solvents?
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Remember:
\[
S_N1 \rightarrow \text{Polar protic solvent}
\]
\[
S_N2 \rightarrow \text{Polar aprotic solvent}
\]
Polar protic solvents stabilize carbocations and thus favor the \(S_N1\) mechanism.
Updated On: Jun 26, 2026
- Polar aprotic solvent
- Non-polar aprotic solvent
- Polar protic solvent
- Non-polar protic solvent
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The Correct Option is C
Solution and Explanation
Step 1: Recall the mechanism of \(S_N1\) reaction.
An \(S_N1\) reaction proceeds through a two-step mechanism.
The first and slowest step is the formation of a carbocation by the departure of the leaving group. \[ R-X \rightarrow R^+ + X^- \] This step determines the rate of the reaction.
Step 2: Understand the role of the solvent.
The carbocation and the leaving group ion formed in the first step are charged species.
A solvent that can strongly solvate and stabilize these ions will facilitate carbocation formation and increase the rate of the \(S_N1\) reaction.
Step 3: Why polar protic solvents are preferred.
Polar protic solvents contain acidic hydrogen atoms and possess high dielectric constants.
Examples include \[ H_2O,\ CH_3OH,\ C_2H_5OH \] These solvents stabilize both \[ R^+ \] and \[ X^- \] through solvation.
As a result, carbocation formation becomes easier and the \(S_N1\) reaction proceeds readily.
Step 4: Analyze the other options.
Polar aprotic solvents generally favor \(S_N2\) reactions because they do not strongly solvate nucleophiles.
Non-polar solvents are poor at stabilizing ions and therefore do not favor carbocation formation.
Hence, they are not suitable for \(S_N1\) reactions.
Step 5: Final conclusion.
Therefore, \(S_N1\) reactions are generally carried out in \[ \boxed{\text{Polar protic solvents}} \] Hence, the correct option is \[ \boxed{(3)} \]
An \(S_N1\) reaction proceeds through a two-step mechanism.
The first and slowest step is the formation of a carbocation by the departure of the leaving group. \[ R-X \rightarrow R^+ + X^- \] This step determines the rate of the reaction.
Step 2: Understand the role of the solvent.
The carbocation and the leaving group ion formed in the first step are charged species.
A solvent that can strongly solvate and stabilize these ions will facilitate carbocation formation and increase the rate of the \(S_N1\) reaction.
Step 3: Why polar protic solvents are preferred.
Polar protic solvents contain acidic hydrogen atoms and possess high dielectric constants.
Examples include \[ H_2O,\ CH_3OH,\ C_2H_5OH \] These solvents stabilize both \[ R^+ \] and \[ X^- \] through solvation.
As a result, carbocation formation becomes easier and the \(S_N1\) reaction proceeds readily.
Step 4: Analyze the other options.
Polar aprotic solvents generally favor \(S_N2\) reactions because they do not strongly solvate nucleophiles.
Non-polar solvents are poor at stabilizing ions and therefore do not favor carbocation formation.
Hence, they are not suitable for \(S_N1\) reactions.
Step 5: Final conclusion.
Therefore, \(S_N1\) reactions are generally carried out in \[ \boxed{\text{Polar protic solvents}} \] Hence, the correct option is \[ \boxed{(3)} \]
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