Question:
Relative lowering in vapour pressure of a solution containing non-volatile solute is the ratio of
Relative lowering in vapour pressure of a solution containing non-volatile solute is the ratio of
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Relative lowering of vapour pressure depends only on the number of solute particles, not on their nature.
Updated On: Feb 18, 2026
- Number of moles of solute to number of moles of solvent
- Number of moles of solvent to total number of moles of solution
- Number of moles of solvent to number of moles of solute
- Number of moles of solute to total number of moles of solution
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The Correct Option is D
Solution and Explanation
Step 1: Recall Raoult’s law.
According to Raoult’s law, relative lowering of vapour pressure is equal to the mole fraction of the solute in the solution.
Step 2: Express the relation mathematically.
\[ \frac{P^0 - P}{P^0} = \frac{n_{\text{solute}}}{n_{\text{solute}} + n_{\text{solvent}}} \]
Step 3: Conclusion.
Thus, relative lowering in vapour pressure is the ratio of number of moles of solute to the total number of moles of solution.
According to Raoult’s law, relative lowering of vapour pressure is equal to the mole fraction of the solute in the solution.
Step 2: Express the relation mathematically.
\[ \frac{P^0 - P}{P^0} = \frac{n_{\text{solute}}}{n_{\text{solute}} + n_{\text{solvent}}} \]
Step 3: Conclusion.
Thus, relative lowering in vapour pressure is the ratio of number of moles of solute to the total number of moles of solution.
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