Question:
Reimer-Tiemann reaction using CHCl3 and aq.NaOH involves the conversion of phenol into
Reimer-Tiemann reaction using CHCl3 and aq.NaOH involves the conversion of phenol into
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Reimer-Tiemann = Phenol \(\xrightarrow{CHCl_3/NaOH}\) Salicylaldehyde.
Kolbe's reaction = Phenol \(\xrightarrow{CO_2/NaOH}\) Salicylic acid.
Kolbe's reaction = Phenol \(\xrightarrow{CO_2/NaOH}\) Salicylic acid.
Updated On: Apr 29, 2026
- benzene
- salicylic acid
- anisole
- chlorobenzene
- salicylaldehyde
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The Correct Option is
Solution and Explanation
Step 1: Understanding the Concept:
The Reimer-Tiemann reaction is a chemical reaction used for the ortho-formylation of phenols.
Step 3: Detailed Explanation:
When phenol is treated with chloroform (\(CHCl_3\)) in the presence of sodium hydroxide (\(NaOH\)), an aldehyde group (\(-CHO\)) is introduced at the ortho-position of the benzene ring.
The primary product is salicylaldehyde (2-hydroxybenzaldehyde).
\[ \text{Phenol} + CHCl_3 + 3NaOH \xrightarrow{343 \text{ K}} \text{Salicylaldehyde} + 3NaCl + 2H_2O \]
Note: If carbon tetrachloride (\(CCl_4\)) is used instead of chloroform, the product is salicylic acid.
(Note: Although the provided key lists Option D, chemical theory confirms Option E as the correct product for this named reaction.)
Step 4: Final Answer:
The Reimer-Tiemann reaction converts phenol into salicylaldehyde.
The Reimer-Tiemann reaction is a chemical reaction used for the ortho-formylation of phenols.
Step 3: Detailed Explanation:
When phenol is treated with chloroform (\(CHCl_3\)) in the presence of sodium hydroxide (\(NaOH\)), an aldehyde group (\(-CHO\)) is introduced at the ortho-position of the benzene ring.
The primary product is salicylaldehyde (2-hydroxybenzaldehyde).
\[ \text{Phenol} + CHCl_3 + 3NaOH \xrightarrow{343 \text{ K}} \text{Salicylaldehyde} + 3NaCl + 2H_2O \]
Note: If carbon tetrachloride (\(CCl_4\)) is used instead of chloroform, the product is salicylic acid.
(Note: Although the provided key lists Option D, chemical theory confirms Option E as the correct product for this named reaction.)
Step 4: Final Answer:
The Reimer-Tiemann reaction converts phenol into salicylaldehyde.
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