Question:

Potassium dichromate (\(\text{K}_2\text{Cr}_2\text{O}_7\)) is a strong oxidizing agent. Select the correct statements from the following:
(A) It is used for preparation of many azo compounds.
(B) With the decreasing pH of the solution, dichromates changes into chromates.
(C) In acidified solution equivalent weight of dichromate is M/5
(D) The bond angle between Cr-O-Cr is \(126^\circ\).
Choose the correct answer from the options given below:

Show Hint

Key dichromate details:
- \(\text{Cr}-\text{O}-\text{Cr}\) bridging angle = \(126^\circ\).
- \(\text{Cr}_2\text{O}_7^{2-}\) in acid has \(n = 6 \implies \text{Eq. Wt.} = M/6\).
- Lower pH (acidic) favors orange \(\text{Cr}_2\text{O}_7^{2-}\); higher pH (basic) favors yellow \(\text{CrO}_4^{2-}\).
Updated On: Sep 7, 2026
  • (A), (B) and (D) only
  • (A), (C) and (D) only
  • (A) and (D) only
  • (B), (C) and (D) only
Show Solution
collegedunia
Verified By Collegedunia

The Correct Option is C

Solution and Explanation

Concept:
Potassium dichromate (\(\text{K}_2\text{Cr}_2\text{O}_7\)) is an important industrial reagent and laboratory standard in volumetric titrations.
Its properties include pH-dependent equilibria between chromate and dichromate, an \(n\)-factor of \(6\) in acid, and a bridged tetrahedral structure with a characteristic bond angle.

Step 1: Evaluation of Statement (A):

Potassium dichromate is widely utilized as an oxidizing agent in organic chemistry, specifically in the dye industry for preparing azo dyes and intermediates.
Hence, statement (A) is correct.

Step 2: Evaluation of Statement (B):

In aqueous solution, chromate (\(\text{CrO}_4^{2-}\), yellow) and dichromate (\(\text{Cr}_2\text{O}_7^{2-}\), orange) exist in a pH-dependent equilibrium:
\[ 2\text{CrO}_4^{2-} + 2\text{H}^+ \rightleftharpoons \text{Cr}_2\text{O}_7^{2-} + \text{H}_2\text{O} \] When the pH decreases (acidic medium, high \([\text{H}^+]\)), Le Chatelier's principle shifts the equilibrium to the right, converting chromates into dichromates.
Conversely, increasing pH (alkaline conditions) shifts the equilibrium to the left, converting dichromate into chromate.
Statement (B) states that decreasing pH converts dichromate to chromate, which is incorrect.

Step 3: Evaluation of Statement (C):

In acidic solution, the reduction half-reaction of dichromate is:
\[ \text{Cr}_2\text{O}_7^{2-} + 14\text{H}^+ + 6e^- \rightarrow 2\text{Cr}^{3+} + 7\text{H}_2\text{O} \] Because each mole of dichromate accepts \(6\) electrons, the \(n\)-factor is \(6\).
The equivalent weight is therefore:
\[ \text{Equivalent Weight} = \frac{\text{Molar Mass}}{6} = \frac{M}{6} \] Statement (C) claims the equivalent weight is \(M/5\), which is incorrect (this value applies to \(\text{KMnO}_4\) in acid).

Step 4: Evaluation of Statement (D):

The dichromate ion consists of two tetrahedral \(\text{CrO}_4\) units sharing a central bridging oxygen atom.
The \(\text{Cr}-\text{O}-\text{Cr}\) bond angle in the dichromate ion is \(126^\circ\).
Hence, statement (D) is correct.
Final Answer:
The correct statements are (A) and (D) only, corresponding to option (C).
Was this answer helpful?
0
0

Top CUET Chemistry Questions

View More Questions

Top CUET General Properties of the Transition Elements (d-Block) Questions

View More Questions