Question:
Phenol is treated with $H_{2}SO_{4}$ to give a product 'X' which on treatment with conc. $HNO_{3}$ gives compound 'Y'. The compounds 'X' and 'Y' are respectively:
Phenol is treated with $H_{2}SO_{4}$ to give a product 'X' which on treatment with conc. $HNO_{3}$ gives compound 'Y'. The compounds 'X' and 'Y' are respectively:
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Picric acid is 2,4,6-trinitrophenol.
Updated On: Apr 28, 2026
- Phenol-2-sulphonic acid and 2-nitrophenol
- Phenol-2-sulphonic acid and 4-nitrophenol
- Phenol-2-sulphonic acid, mixture of 2-nitrophenol and 4-nitrophenol
- Phenol-2,4-disulphonic acid, mixture of 2-nitrophenol and 4-nitrophenol
- Phenol-2,4-disulphonic acid and picric acid
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The Correct Option is
Solution and Explanation
Step 1: Concept
Sulphonation of phenol followed by nitration is a route to avoid oxidation of phenol.
Step 2: Meaning
Excess acid leads to multiple substitutions on the highly activated ring.
Step 3: Analysis
$H_2SO_4$ creates phenol-2,4-disulphonic acid (X). Conc. $HNO_3$ then replaces sulphonic groups to form 2,4,6-trinitrophenol, known as picric acid (Y).
Step 4: Conclusion
X is Phenol-2,4-disulphonic acid and Y is picric acid. Final Answer: (E)
Sulphonation of phenol followed by nitration is a route to avoid oxidation of phenol.
Step 2: Meaning
Excess acid leads to multiple substitutions on the highly activated ring.
Step 3: Analysis
$H_2SO_4$ creates phenol-2,4-disulphonic acid (X). Conc. $HNO_3$ then replaces sulphonic groups to form 2,4,6-trinitrophenol, known as picric acid (Y).
Step 4: Conclusion
X is Phenol-2,4-disulphonic acid and Y is picric acid. Final Answer: (E)
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