Question:
Oxidation number of potassium in \( K_{2}O \), \( K_{2}O_{2} \) and \( KO_{2} \), respectively, is:
Oxidation number of potassium in \( K_{2}O \), \( K_{2}O_{2} \) and \( KO_{2} \), respectively, is:
Show Hint
Don't let the complex oxygen states (peroxides and superoxides) confuse you. In almost every chemical environment, Group 1 metals (Li, Na, K, Rb, Cs) are strictly \(+1\). It is the oxidation state of oxygen that varies to balance the charge.
Updated On: Apr 22, 2026
- \(+2\), \(+1\) and \(+\frac{1}{2}\)
- \(+1\), \(+1\) and \(+1\)
- \(+1\), \(+4\) and \(+2\)
- \(+1\), \(+2\) and \(+4\)
Show Solution
Verified By Collegedunia
The Correct Option is B
Solution and Explanation
Step 1: Understanding the Concept:
Potassium (K) is an alkali metal belonging to Group 1 of the periodic table. Alkali metals have a single valence electron in their outermost shell, which they lose very easily to achieve a stable noble gas configuration.
Step 2: Detailed Explanation:
1. Alkali metals, including potassium, always exhibit an oxidation state of \(+1\) in their compounds.
2. In \(K_2O\) (Potassium oxide), oxygen is in the \(-2\) state. Calculation: \(2(x) + (-2) = 0 \implies x = +1\).
3. In \(K_2O_2\) (Potassium peroxide), oxygen is in the \(-1\) state (peroxide ion \(O_2^{2-}\)). Calculation: \(2(x) + 2(-1) = 0 \implies x = +1\).
4. In \(KO_2\) (Potassium superoxide), oxygen is in the \(-1/2\) state (superoxide ion \(O_2^{-}\)). Calculation: \(x + 2(-1/2) = 0 \implies x = +1\).
Step 3: Final Answer
The oxidation number of potassium remains \(+1\) in all three compounds.
Potassium (K) is an alkali metal belonging to Group 1 of the periodic table. Alkali metals have a single valence electron in their outermost shell, which they lose very easily to achieve a stable noble gas configuration.
Step 2: Detailed Explanation:
1. Alkali metals, including potassium, always exhibit an oxidation state of \(+1\) in their compounds.
2. In \(K_2O\) (Potassium oxide), oxygen is in the \(-2\) state. Calculation: \(2(x) + (-2) = 0 \implies x = +1\).
3. In \(K_2O_2\) (Potassium peroxide), oxygen is in the \(-1\) state (peroxide ion \(O_2^{2-}\)). Calculation: \(2(x) + 2(-1) = 0 \implies x = +1\).
4. In \(KO_2\) (Potassium superoxide), oxygen is in the \(-1/2\) state (superoxide ion \(O_2^{-}\)). Calculation: \(x + 2(-1/2) = 0 \implies x = +1\).
Step 3: Final Answer
The oxidation number of potassium remains \(+1\) in all three compounds.
Was this answer helpful?
0
0
Top KEAM Chemistry Questions
- The pH of a solution obtained by mixing 60 mL of 0.1 M BaOH solution at 40m of 0.15m HCI solution is
- $4\, g$ of copper was dissolved in concentrated nitric acid. The copper nitrate solution on strong heating gave $5\, g$ of its oxide. The equivalent weight of copper is :
- Green chemistry deals with
- Neopentyl bromide undergoes dehydrohalogenation to give alkenes even though it has no $\beta$- hydrogen. This is due to
- Plot of $ log\text{ }x/m $ against log $p$ is a straight line inclined at an angle of $ 45{}^\circ $ . When the pressure is $ 0.5 \,arm $ and Freundlich parameter. $ k $ is $ 10 $ , the amount of solute adsorbed per gram of adsorbent will be $ (log\text{ }5=0.6990) $
View More Questions
Top KEAM Oxidation Number And Oxidation States Questions
Top KEAM Questions
- i.$\quad$ They help in respiration ii.$\quad$ They help in cell wall formation iii.$\quad$ They help in DNA replication iv. $\quad$They increase surface area of plasma membrane Which of the following prokaryotic structures has all the above roles?
- A body oscillates with SHM according to the equation (in SI units), $x = 5 cos \left(2\pi t +\frac{\pi}{4}\right) .$ Its instantaneous displacement at $t = 1$ second is
- The pH of a solution obtained by mixing 60 mL of 0.1 M BaOH solution at 40m of 0.15m HCI solution is
Kepler's second law (law of areas) of planetary motion leads to law of conservation of
- If $\int e^{2x}f' \left(x\right)dx =g \left(x\right)$, then $ \int\left(e^{2x}f\left(x\right) + e^{2x} f' \left(x\right)\right)dx =$
View More Questions