Question:

One mole of a yellow coloured complex CoCl\(_3\cdot\)6NH\(_3\) gave three moles of AgCl on reaction with an excess of AgNO\(_3\). The conductivity of the solution of the complex is due to:

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For ionic complexes, the total number of ions in solution determines conductivity. Count cations + anions after dissociation.
Updated On: Jun 19, 2026
  • 1 ion mol\(^{-1}\)
  • 2 ions mol\(^{-1}\)
  • 3 ions mol\(^{-1}\)
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The Correct Option is D

Solution and Explanation

Step 1: Identify the type of complex.
The complex is \([\text{Co(NH}_3)_6]\text{Cl}_3\), a typical hexamminecobalt(III) chloride. When dissolved, the cation is \([\text{Co(NH}_3)_6]^{3+}\) and there are three Cl\(^-\) ions.

Step 2: Reaction with AgNO\(_3\).

Each Cl\(^-\) reacts with Ag\(^+\) to form AgCl: \[ 3\text{Cl}^- + 3\text{Ag}^+ \rightarrow 3\text{AgCl} \] Thus, the number of ions produced in solution = 1 cation + 3 anions = 4 ions.

Step 3: Conductivity explanation.

Conductivity of solution depends on total number of ions. Here, \([\text{Co(NH}_3)_6]^{3+}\) + 3 Cl\(^-\) = 4 ions per mole of complex.

Step 4: Final conclusion.

Hence, the molar conductivity corresponds to: \[ \boxed{4\, \text{ions mol}^{-1}} \]
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