Question:
One mole of $A(g)$ was taken in a 1L closed flask and heated to T(K). At equilibrium, the concentration of $A(g)$ is equal to four times the equilibrium concentration of $B(g)$. What is $K_c$ for $A(g) \rightleftharpoons B(g) + C(g)$?
One mole of $A(g)$ was taken in a 1L closed flask and heated to T(K). At equilibrium, the concentration of $A(g)$ is equal to four times the equilibrium concentration of $B(g)$. What is $K_c$ for $A(g) \rightleftharpoons B(g) + C(g)$?
Show Hint
Always define the equilibrium expression clearly from the balanced equation.
Updated On: Jun 6, 2026
- 0.02
- 0.04
- 0.05
- 0.06
Show Solution
Verified By Collegedunia
The Correct Option is C
Solution and Explanation
Step 1: Concept
Equilibrium constant $K_c = [B][C] / [A]$.
Step 2: Meaning
Let $[B] = y$. Then $[A] = 4y$. Initial moles = 1. $[A]_{eq} = 1 - x$, $[B] = x$, $[C] = x$. Given $[A] = 4[B]$, so $1 - x = 4x \implies 5x = 1 \implies x = 0.2$. $[A] = 0.8$, $[B] = 0.2$, $[C] = 0.2$.
Step 3: Analysis
$K_c = (0.2 \times 0.2) / 0.8 = 0.04 / 0.8 = 0.05$.
Step 4: Conclusion
The value of $K_c$ is 0.05.
Final Answer: (C)
Equilibrium constant $K_c = [B][C] / [A]$.
Step 2: Meaning
Let $[B] = y$. Then $[A] = 4y$. Initial moles = 1. $[A]_{eq} = 1 - x$, $[B] = x$, $[C] = x$. Given $[A] = 4[B]$, so $1 - x = 4x \implies 5x = 1 \implies x = 0.2$. $[A] = 0.8$, $[B] = 0.2$, $[C] = 0.2$.
Step 3: Analysis
$K_c = (0.2 \times 0.2) / 0.8 = 0.04 / 0.8 = 0.05$.
Step 4: Conclusion
The value of $K_c$ is 0.05.
Final Answer: (C)
Was this answer helpful?
0
0
Top AP EAPCET Chemistry Questions
- The four quantum numbers of the valence electron of potassium are :
- The volume of $0.02\, M$ acidified permanganate solution required for complete reaction of $60\, mL$ of $0.01\, MI^{-}$ ion solution to form $I_2$ in $mL$ is
- In which of the following the election gain enthalpy of elements is correctly arranged?
- The radii of $ \text{F,}{{\text{F}}^{-}}\text{O} $ and $ {{\text{O}}^{2-}} $ are in the order
- Which of the following has the highest first ionization potential?
View More Questions
Top AP EAPCET Chemical equilibria Questions
- Observe the following equilibrium at T(K) \[ H_2(g) + I_2(g) \rightleftharpoons 2HI(g) \] Which one of the following does not disturb the above equilibrium?
- Consider the equilibrium reactions:
\(H_3PO_4 \rightleftharpoons H^+ + H_2PO_4^-\) \((K_1)\)
\(H_2PO_4^- \rightleftharpoons H^+ + HPO_4^{2-}\) \((K_2)\)
\(HPO_4^{2-} \rightleftharpoons H^+ + PO_4^{3-}\) \((K_3)\)
The equilibrium constant, \(K_c\), for the following dissociation:
\(H_3PO_4 \rightleftharpoons 3H^+ + PO_4^{3-}\)
is: - Which one of the pairs will form a buffer solution?
- For the reaction $\text{N}_2\text{(g)} + 3\text{H}_2\text{(g)} \rightleftharpoons 2\text{NH}_3\text{(g)}$, the relation between $K_p$ and $K_c$ is
- The conjugate base of $\text{H}_{2}\text{PO}_{4}^{-}$ is
View More Questions
Top AP EAPCET Questions
- A body is projected from the ground at an angle of $\tan^{-1} \left( \frac{8}{7}\right)$ with the horizontal. The ratio of the maximum height attained by it to its range is
- The four quantum numbers of the valence electron of potassium are :
- A lens forms real and virtual images of an object, when the object is at $u_{1}$ and $u_{2}$ distances respectively. If the size of the virtual image is double that of the real image, then the focal length of the lens is (take, the magnification of the real image as $m$ )
- Two spheres $P$ and $Q$, each of mass $200\, g$ are attached to a string of length one metre as shown in the figure. The string and the spheres are then whirled in a horizontal circle about $O$ at a constant angular speed. The ratio of the tension in the string between $P$ and $Q$ to that of between $P$ and $O$ is $(P$ is at mid-point of the line joining $O$ and $Q$ )
- The volume of $0.02\, M$ acidified permanganate solution required for complete reaction of $60\, mL$ of $0.01\, MI^{-}$ ion solution to form $I_2$ in $mL$ is
View More Questions