Step 1: Understanding the Question:
The question asks to identify which of the given mixtures of chemical species will act as a buffer solution.
Step 2: Detailed Explanation:
• A buffer solution is an aqueous solution that resists changes in its pH level upon the addition of small amounts of a strong acid or a strong base.
• Buffer solutions are of two primary types:
- Acidic Buffer: Formed by mixing a weak acid and its salt with a strong base (e.g., $\text{CH}_3\text{COOH}$ and $\text{CH}_3\text{COONa}$).
- Basic Buffer: Formed by mixing a weak base and its salt with a strong acid (e.g., $\text{NH}_4\text{OH}$ and $\text{NH}_4\text{Cl}$).
• Let us analyze each of the given options:
• Option (A): $\text{CH}_3\text{COONa}$ is a salt of a weak acid and a strong base, and $\text{NaOH}$ is a strong base. Since there is no weak acid or weak base present, this pair cannot act as a buffer solution.
• Option (B): $\text{CH}_3\text{COONH}_4$ is a salt of a weak acid and weak base, and $\text{NH}_4\text{Cl}$ is a salt of a weak base and strong acid. A mixture of two salts does not form a standard buffer solution.
• Option (C): $\text{NH}_4\text{OH}$ is a weak base, and $\text{NH}_4\text{Cl}$ is its conjugate salt formed with a strong acid ($\text{HCl}$). This matches the exact definition of a basic buffer solution. Therefore, this pair will form a buffer.
• Option (D): $\text{CH}_3\text{COONa}$ is a salt and $\text{HCl}$ is a strong acid. Although they can react to form a weak acid ($\text{CH}_3\text{COOH}$), the given pair itself is not a buffer mixture unless mixed in specific non-stoichiometric ratios where the weak acid is generated in excess alongside its salt. Among the direct choices, Option (C) is the classic basic buffer.
Step 3: Final Answer:
The pair that will form a buffer solution is $\text{NH}_4\text{Cl}$ & $\text{NH}_4\text{OH}$.