Question:
Observe the following statements:
I) Second ionization enthalpy of Be is smaller than lithium
II) Hydration enthalpy of Mg\(^{2+}\) is greater than Be\(^{2+}\)
III) Ionic radius of Li\(^+\) is greater than Be\(^{2+}\)
Correct statements are:
Observe the following statements:
I) Second ionization enthalpy of Be is smaller than lithium
II) Hydration enthalpy of Mg\(^{2+}\) is greater than Be\(^{2+}\)
III) Ionic radius of Li\(^+\) is greater than Be\(^{2+}\)
Correct statements are:
Show Hint
Higher nuclear charge and fewer electrons lead to smaller ionic radius.
Updated On: Jun 19, 2026
- I, II only
- II, III only
- I, III only
- I, II, III
Show Solution
Verified By Collegedunia
The Correct Option is B
Solution and Explanation
Step 1: Evaluating statement I.
Second ionization enthalpy of Be is actually higher than Li because removing an electron from fully filled 2s orbital in Be is more difficult. Hence statement I is false.
Step 2: Evaluating statement II.
Hydration enthalpy increases with higher charge density. Be\(^{2+}\) has smaller ionic radius and higher charge density than Mg\(^{2+}\), so Be\(^{2+}\) has greater hydration enthalpy. Hence statement II is false as given.
Step 3: Evaluating statement III.
Li\(^+\) has more electrons and larger size compared to Be\(^{2+}\). Thus Li\(^+\) has greater ionic radius than Be\(^{2+}\). So statement III is correct.
Step 4: Final verification.
Only statement III is correct based on periodic and ionic size trends.
Step 5: Final conclusion.
Correct option is II, III only
Final Answer: \[ \boxed{\text{II, III only}} \]
Second ionization enthalpy of Be is actually higher than Li because removing an electron from fully filled 2s orbital in Be is more difficult. Hence statement I is false.
Step 2: Evaluating statement II.
Hydration enthalpy increases with higher charge density. Be\(^{2+}\) has smaller ionic radius and higher charge density than Mg\(^{2+}\), so Be\(^{2+}\) has greater hydration enthalpy. Hence statement II is false as given.
Step 3: Evaluating statement III.
Li\(^+\) has more electrons and larger size compared to Be\(^{2+}\). Thus Li\(^+\) has greater ionic radius than Be\(^{2+}\). So statement III is correct.
Step 4: Final verification.
Only statement III is correct based on periodic and ionic size trends.
Step 5: Final conclusion.
Correct option is II, III only
Final Answer: \[ \boxed{\text{II, III only}} \]
Was this answer helpful?
0
0
Top AP EAPCET Chemistry Questions
- The four quantum numbers of the valence electron of potassium are :
- The volume of $0.02\, M$ acidified permanganate solution required for complete reaction of $60\, mL$ of $0.01\, MI^{-}$ ion solution to form $I_2$ in $mL$ is
- In which of the following the election gain enthalpy of elements is correctly arranged?
- The radii of $ \text{F,}{{\text{F}}^{-}}\text{O} $ and $ {{\text{O}}^{2-}} $ are in the order
- Which of the following has the highest first ionization potential?
View More Questions
Top AP EAPCET anomalous behaviour of lithium Questions
Top AP EAPCET Questions
- A body is projected from the ground at an angle of $\tan^{-1} \left( \frac{8}{7}\right)$ with the horizontal. The ratio of the maximum height attained by it to its range is
- The four quantum numbers of the valence electron of potassium are :
- A lens forms real and virtual images of an object, when the object is at $u_{1}$ and $u_{2}$ distances respectively. If the size of the virtual image is double that of the real image, then the focal length of the lens is (take, the magnification of the real image as $m$ )
- Two spheres $P$ and $Q$, each of mass $200\, g$ are attached to a string of length one metre as shown in the figure. The string and the spheres are then whirled in a horizontal circle about $O$ at a constant angular speed. The ratio of the tension in the string between $P$ and $Q$ to that of between $P$ and $O$ is $(P$ is at mid-point of the line joining $O$ and $Q$ )
- The volume of $0.02\, M$ acidified permanganate solution required for complete reaction of $60\, mL$ of $0.01\, MI^{-}$ ion solution to form $I_2$ in $mL$ is
View More Questions