Question:
Observe the following set of reactions
\[
Y \xrightarrow[\text{NaNH}_2(l)]{} \mathrm{C_2H_2}
\xrightarrow[\mathrm{H_2}/\mathrm{Pt}]{} X
\]
Hybridization of carbon in \(X\) and \(Y\), respectively is
Observe the following set of reactions
\[
Y \xrightarrow[\text{NaNH}_2(l)]{} \mathrm{C_2H_2}
\xrightarrow[\mathrm{H_2}/\mathrm{Pt}]{} X
\]
Hybridization of carbon in \(X\) and \(Y\), respectively is
Show Hint
Hybridization of carbon:
\begin{itemize}
\item Single bond \(\rightarrow sp^3\)
\item Double bond \(\rightarrow sp^2\)
\item Triple bond \(\rightarrow sp\)
\end{itemize}
Hydrogenation converts multiple bonds into single bonds, increasing the hybridization from \(sp\) to \(sp^3\).
Updated On: Jul 9, 2026
- \(sp,\;sp^2\)
- \(sp^3,\;sp^3\)
- \(sp^2,\;sp^3\)
- \(sp^3,\;sp\) \bigskip
Show Solution
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The Correct Option is D
Solution and Explanation
Step 1: Identify \(X\).
Hydrogenation of acetylene in the presence of Pt gives ethane.
\[
\mathrm{C_2H_2}+2\mathrm{H_2}
\rightarrow
\mathrm{C_2H_6}
\]
Thus,
\[
X=\mathrm{C_2H_6}
\]
The carbon atoms in ethane are
\[
\boxed{sp^3\text{-hybridised}.}
\]
Step 2: Identify \(Y\). Liquid ammonia with sodium amide is used for double dehydrohalogenation of vicinal/geminal dihalides to form acetylene. Therefore, \(Y\) contains carbon atoms with \[ \boxed{sp\text{-hybridisation}.} \]
Step 3: Final conclusion. Hence, the hybridization of carbon in \(X\) and \(Y\), respectively is \[ \boxed{sp^3,\;sp} \] Therefore, the correct option is \(\boxed{(D)}\).
Step 2: Identify \(Y\). Liquid ammonia with sodium amide is used for double dehydrohalogenation of vicinal/geminal dihalides to form acetylene. Therefore, \(Y\) contains carbon atoms with \[ \boxed{sp\text{-hybridisation}.} \]
Step 3: Final conclusion. Hence, the hybridization of carbon in \(X\) and \(Y\), respectively is \[ \boxed{sp^3,\;sp} \] Therefore, the correct option is \(\boxed{(D)}\).
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