Question:
Observe the following reaction
\[
\mathrm{C_6H_5N_2Cl}
\xrightarrow[\text{cold}]{X}
Y
\]
\(Y\) reacts with aqueous NaOH solution and forms its sodium salt. What are \(X\) and \(Y\)?
Observe the following reaction
\[
\mathrm{C_6H_5N_2Cl}
\xrightarrow[\text{cold}]{X}
Y
\]
\(Y\) reacts with aqueous NaOH solution and forms its sodium salt. What are \(X\) and \(Y\)?
Show Hint
Benzenediazonium chloride:
- With water \(\rightarrow\) Phenol.
- With KI \(\rightarrow\) Iodobenzene.
- With CuCl/HCl \(\rightarrow\) Chlorobenzene.
- With CuBr/HBr \(\rightarrow\) Bromobenzene.
Updated On: Jul 9, 2026
- \(\mathrm{C_2H_5OH}\); Phenol
- \(\mathrm{C_2H_5OH}\); \(p\)-Cresol
- \(\mathrm{H_2O}\); \(p\)-Cresol
- \(\mathrm{H_2O}\); Phenol \bigskip
Show Solution
Verified By Collegedunia
The Correct Option is D
Solution and Explanation
Step 1: Identify reagent \(X\).
Benzenediazonium chloride undergoes hydrolysis on warming with water.
\[
\mathrm{C_6H_5N_2^+Cl^-}
+\mathrm{H_2O}
\rightarrow
\mathrm{C_6H_5OH}
+\mathrm{N_2}
+\mathrm{HCl}
\]
Thus,
\[
X=\mathrm{H_2O}
\]
Step 2: Identify product \(Y\). The product formed is phenol. Phenol reacts with aqueous NaOH to form sodium phenoxide. \[ \mathrm{C_6H_5OH} +\mathrm{NaOH} \rightarrow \mathrm{C_6H_5ONa} +\mathrm{H_2O} \] Hence, \[ Y=\mathrm{Phenol} \]
Step 3: Final conclusion. Therefore, \[ \boxed{X=\mathrm{H_2O},\qquad Y=\mathrm{Phenol}} \] Hence, the correct option is \(\boxed{(D)}\).
Step 2: Identify product \(Y\). The product formed is phenol. Phenol reacts with aqueous NaOH to form sodium phenoxide. \[ \mathrm{C_6H_5OH} +\mathrm{NaOH} \rightarrow \mathrm{C_6H_5ONa} +\mathrm{H_2O} \] Hence, \[ Y=\mathrm{Phenol} \]
Step 3: Final conclusion. Therefore, \[ \boxed{X=\mathrm{H_2O},\qquad Y=\mathrm{Phenol}} \] Hence, the correct option is \(\boxed{(D)}\).
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