Step 1: Analysis
o-toluic acid contains a methyl group ($-CH_{3}$) and a carboxylic acid group ($-COOH$).
Step 2: Directing Effects
- $-CH_{3}$ is an activating, ortho/para directing group.
- $-COOH$ is a deactivating, meta directing group.
Step 3: Conclusion
Both groups direct the incoming electrophile ($Br^+$) to the same position. In the major product, Bromine is para to $-CH_{3}$ and meta to $-COOH$.
Final Answer: (C)