Question

In the following sequence of reactions, \[ CH_3Br \xrightarrow{KCN} X \xrightarrow{H_3O^+} Y \xrightarrow{LiAlH_4 / \text{ether}} Z \] The final product \(Z\) is:

• A. acetone
  % option (B) methane
• B. acetaldehyde
• C. ethyl alcohol
• D. methane

Hint:

Nitrile → acid → alcohol is a common reaction chain.

Answer 1

The Correct Option is C

Concept:
•\(KCN\) → nucleophilic substitution → nitrile formation
•Hydrolysis of nitrile → carboxylic acid
•\(LiAlH_4\) reduces acid → alcohol

Step 1: \[ CH_3Br \xrightarrow{KCN} CH_3CN \quad (X) \]

Step 2: \[ CH_3CN \xrightarrow{H_3O^+} CH_3COOH \quad (Y) \]

Step 3: \[ CH_3COOH \xrightarrow{LiAlH_4} CH_3CH_2OH \quad (Z) \] Final: \[ Z = \text{ethyl alcohol} \]