Question:
\( C_6H_6 \xrightarrow{350 \, K, \, H_2SO_4} A \xrightarrow{\text{Alkali Fusion}} B \xrightarrow{\text{Br}_2/\text{H}_2O} C \). In the above sequence, C is ________.
\( C_6H_6 \xrightarrow{350 \, K, \, H_2SO_4} A \xrightarrow{\text{Alkali Fusion}} B \xrightarrow{\text{Br}_2/\text{H}_2O} C \). In the above sequence, C is ________.
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$C6H6 \xrightarrow350 K, H2SO4 A \xrightarrowAlkali Fusion B \xrightarrowBr2/H2O C$. In the above sequence, C is ____.
Updated On: Apr 15, 2026
- o-bromophenol
- p-bromophenol
- m-bromophenol
- 2, 4, 6-tribromophenol
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The Correct Option is D
Solution and Explanation
Step 1: Path to A
Benzene + $H_{2}SO_{4} \rightarrow$ Benzene sulphonic acid (A).
Step 2: Path to B
Alkali fusion of (A) converts the $-SO_{3}H$ group into a hydroxyl group, giving Phenol (B).
Step 3: Path to C
Phenol reacts with excess bromine water ($Br_{2}/H_{2}O$) to undergo poly-substitution.
Step 4: Conclusion
The final product C is 2, 4, 6-tribromophenol.
Final Answer: (D)
Benzene + $H_{2}SO_{4} \rightarrow$ Benzene sulphonic acid (A).
Step 2: Path to B
Alkali fusion of (A) converts the $-SO_{3}H$ group into a hydroxyl group, giving Phenol (B).
Step 3: Path to C
Phenol reacts with excess bromine water ($Br_{2}/H_{2}O$) to undergo poly-substitution.
Step 4: Conclusion
The final product C is 2, 4, 6-tribromophenol.
Final Answer: (D)
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