Question:
Nuclear reactor in which U-235 is used as fuel uses 2 kg of U-235 in 30 days. Then, power output of the reactor will be (given energy released per fission = 185 MeV):
Nuclear reactor in which U-235 is used as fuel uses 2 kg of U-235 in 30 days. Then, power output of the reactor will be (given energy released per fission = 185 MeV):
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$1$ eV = $1.6 × 10^-19$ J.
Updated On: Apr 16, 2026
- 43.5 MW
- 58.5 MW
- 69.6 MW
- 73.1 MW
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Verified By Collegedunia
The Correct Option is B
Solution and Explanation
Step 1: Number of atoms in 2 kg: $N = \frac2 × 10³235 × 6.023 × 10²3 = 5.12 × 10²4$.
Step 2: Energy = $5.12 × 10²4 × 185 × 1.6 × 10^-13 = 1.515 × 10¹4$ J. Power = $\frac1.515 × 10¹430 × 24 × 3600 = 58.5$ MW.
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