What will be the equilibrium constant of the given reaction carried out in a \(5 \,L\) vessel and having equilibrium amounts of \(A_2\) and \(A\) as \(0.5\) mole and \(2 \times 10^{-6}\) mole respectively?
The reaction : \(A_2 \rightleftharpoons 2A\)

Cobalt chloride when dissolved in water forms pink colored complex $X$ which has octahedral geometry. This solution on treating with cone $HCl$ forms deep blue complex, $\underline{Y}$ which has a $\underline{Z}$ geometry $X, Y$ and $Z$, respectively, are
A group 15 element forms \( d\pi - d\pi \) bond with transition metals. It also forms a hydride, which is the strongest base among the hydrides of other group members that form \( d\pi - d\pi \) bonds. The atomic number of the element is …….
What will be the equilibrium constant of the given reaction carried out in a \(5 \,L\) vessel and having equilibrium amounts of \(A_2\) and \(A\) as \(0.5\) mole and \(2 \times 10^{-6}\) mole respectively?
The reaction : \(A_2 \rightleftharpoons 2A\)
The ones that are anions of a hydrogen atom are hydrides. Hydrogen can act or respond to different elements of the periodic desk. Nucleophilic, decreasing, and fundamental properties may be found in the interior of the chemicals of hydrogen, and hydride. Hydride compounds are devised with all factors of the periodic table, excluding a few noble gases. Hydrides are common compounds of hydrogen but with lesser electronegative elements.
Depending upon the evolution of a chemical bond and the elements that can act with the hydrogen atoms, there are three types of hydrides: