Statement-I : Among \(15^{th}\) group hydrides reducing character decreases from
\(NH_3\) to \(BiH_3\).
Statement-II : \(E_2O_3\) and \(E_2O_5\) are always basic. [Where \(E\) is group \(15\) element]
\(NH_3\) to \(BiH_3\).
Statement-II : \(E_2O_3\) and \(E_2O_5\) are always basic. [Where \(E\) is group \(15\) element]
- Both statement-I and Statement-II are correct
- Statement-I is correct and Statement-II is false
- Statement-I is false and Statement-II is correct
- Both Statement-I and Statement-II are false
The Correct Option is A
Solution and Explanation
The Correct Option is (B) : \(\text{Statement-I is correct and Statement-II is false}\)
Top Questions on Hydrides
- Consider the following statements:
Statement-I: H$_2$Se is more acidic than H$_2$Te.
Statement-II: H$_2$Se has higher bond dissociation enthalpy than H$_2$Te.
In light of the above statements, choose the correct option: A group 15 element forms \( d\pi - d\pi \) bond with transition metals. It also forms a hydride, which is the strongest base among the hydrides of other group members that form \( d\pi - d\pi \) bonds. The atomic number of the element is …….
- Identify the hydride which is not correctly matched with the example given in brackets.
- Which of the following reactions give $\mathrm{H_2}$ as one of the products? (Reactions are not balanced.)
- $\mathrm{NaBH_4 + I_2}$
- $\mathrm{B_2H_6 + N(CH_3)_3}$
- $\mathrm{Al + NaOH + H_2O}$
- $\mathrm{BF_3 + NaH}$
- What is the order of reducing character for \(AsH_3, NH_3, PH_3\) (group \(15\) hydrides)?
Questions Asked in JEE Main exam
Two p-n junction diodes \(D_1\) and \(D_2\) are connected as shown in the figure. \(A\) and \(B\) are input signals and \(C\) is the output. The given circuit will function as a _______.
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- Let $\vec{a}=2\hat{i}-\hat{j}-\hat{k}$, $\vec{b}=\hat{i}+3\hat{j}-\hat{k}$ and $\vec{c}=2\hat{i}+\hat{j}+3\hat{k}$. Let $\vec{v}$ be the vector in the plane of $\vec{a}$ and $\vec{b}$, such that the length of its projection on the vector $\vec{c}$ is $\dfrac{1}{\sqrt{14}}$. Then $|\vec{v}|$ is equal to
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A substance 'X' (1.5 g) dissolved in 150 g of a solvent 'Y' (molar mass = 300 g mol$^{-1}$) led to an elevation of the boiling point by 0.5 K. The relative lowering in the vapour pressure of the solvent 'Y' is $____________ \(\times 10^{-2}\). (nearest integer)
[Given : $K_{b}$ of the solvent = 5.0 K kg mol$^{-1}$]
Assume the solution to be dilute and no association or dissociation of X takes place in solution.- JEE Main - 2026
- Solutions
Concepts Used:
Hydrides
The ones that are anions of a hydrogen atom are hydrides. Hydrogen can act or respond to different elements of the periodic desk. Nucleophilic, decreasing, and fundamental properties may be found in the interior of the chemicals of hydrogen, and hydride. Hydride compounds are devised with all factors of the periodic table, excluding a few noble gases. Hydrides are common compounds of hydrogen but with lesser electronegative elements.
Types of Hydrides:
Depending upon the evolution of a chemical bond and the elements that can act with the hydrogen atoms, there are three types of hydrides:
- Ionic Hydrides
- Covalent Hydrides
- Metallic or Interstitial Hydrides