Question:

Mobility of electrons in a semiconductor is defined as the ratio of their drift velocity to the applied electric field. If, for an n-type semiconductor, the density of electrons is \(10^{19}\ \mathrm{m^{-3}}\) and their mobility is \(1.6\ \mathrm{m^2/(V.s)}\) then the resistivity of the semiconductor (since it is an n-type semiconductor contribution of holes is ignored) is close to :

Show Hint

Conductivity \(\sigma=n_ee\mu_e\) and resistivity \(\rho=1/\sigma\).
Updated On: Nov 5, 2026
  • \(2\ \Omega\mathrm{m}\)
  • \(4\ \Omega\mathrm{m}\)
  • \(0.4\ \Omega\mathrm{m}\)
  • \(0.2\ \Omega\mathrm{m}\)
Show Solution
collegedunia
Verified By Collegedunia

The Correct Option is C

Solution and Explanation

\(J=n e v_d=n e\mu E\Rightarrow\sigma=ne\mu\).
\(\sigma=10^{19}\times1.6\times10^{-19}\times1.6=2.56\ \mathrm{(\Omega m)^{-1}}\).
\(\rho=\frac1\sigma=\frac{1}{2.56}\approx0.39\ \Omega\mathrm m\approx0.4\ \Omega\mathrm m\).
Answer: (3) \(0.4\ \Omega\mathrm{m}\)
Was this answer helpful?
0
0

Top JEE Main Physics Questions

View More Questions

Top JEE Main Semiconductor electronics: materials, devices and simple circuits Questions

View More Questions