\(\mathrm{C_6H_5NO_2}\) \(\xrightarrow{\ \mathrm{Sn+HCl}\ }\) "A" \(\xrightarrow[\ \mathrm{H^{+}}\ ]{\ \mathrm{C_6H_5N_2^{+}Cl^{-}}\ }\) P (Yellow coloured Compound)
Consider the above reaction, the product "P" is :
Consider the above reaction, the product "P" is :
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The Correct Option is B
Solution and Explanation
Step 2: Aniline reacts with benzenediazonium chloride in weakly acidic medium by azo coupling (electrophilic substitution) at the para position of the activated ring.
The product is \(\mathrm{p}\)-aminoazobenzene (4-aminoazobenzene), \(\mathrm{C_6H_5{-}N{=}N{-}C_6H_4{-}NH_2}\), a yellow dye.
Option (1) is the ortho isomer, (3) diphenylamine and (4) diazoaminobenzene; the correct structure is option (2).
Answer: (2) p-aminoazobenzene
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