Question:

Match the LIST-I with LIST-II. LIST-I: A. Nullisomic, B. Monosomic, C. Trisomic, D. Tetrasomic. LIST-II: I. \(2n+1\), II. \(2n+2\), III. \(2n-2\), IV. \(2n-1\).

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Nullisomic \(=2n-2\), Monosomic \(=2n-1\), Trisomic \(=2n+1\), and Tetrasomic \(=2n+2\).
Updated On: May 18, 2026
  • A-II, B-IV, C-I, D-III
  • A-I, B-III, C-II, D-IV
  • A-III, B-IV, C-I, D-II
  • A-I, B-II, C-IV, D-III
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The Correct Option is C

Solution and Explanation

Concept:
Aneuploidy means change in chromosome number due to loss or gain of one or more chromosomes.

Step 1: Nullisomic.

Nullisomic means loss of both chromosomes of a homologous pair. \[ 2n-2 \] So, \[ A\rightarrow III \]

Step 2: Monosomic.

Monosomic means loss of one chromosome. \[ 2n-1 \] So, \[ B\rightarrow IV \]

Step 3: Trisomic.

Trisomic means addition of one extra chromosome. \[ 2n+1 \] So, \[ C\rightarrow I \]

Step 4: Tetrasomic.

Tetrasomic means addition of two extra chromosomes of the same pair. \[ 2n+2 \] So, \[ D\rightarrow II \] Therefore, \[ A-III,\ B-IV,\ C-I,\ D-II \] \[ \therefore \text{Correct Answer is (C)} \]
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