Question:

Match the following orders with their properties.

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Transition metal properties depend strongly on number of unpaired d-electrons because stronger metallic bonding increases melting point and atomization enthalpy.
Updated On: Jun 15, 2026
  • A-I, B-II, C-I, D-IV
  • A-II, B-I, C-IV, D-III
  • A-IV, B-III, C-II, D-I
  • A-III, B-IV, C-II, D-I
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The Correct Option is D

Solution and Explanation

Concept: Transition metals show characteristic periodic trends because of partially filled d-orbitals. Important properties include:
• Enthalpy of atomization
• Density
• Metallic radius
• Melting point Each property follows trends based on bonding strength and atomic structure.

Step 1:
Identify enthalpy of atomization. Strong metallic bonding gives high atomization enthalpy. Order: \[ Fe& gt;Cr& gt;Mn \] Thus \[ A\rightarrow III \]

Step 2:
Identify density trend. Density depends on atomic mass and packing. Order: \[ Co& gt;Fe& gt;Mn \] Thus \[ B\rightarrow IV \]

Step 3:
Identify metallic radius trend. Across period radius decreases. Order: \[ Ti& gt;V& gt;Cr \] Thus \[ C\rightarrow II \]

Step 4:
Identify melting point trend. Melting point depends on bond strength. Order: \[ Cr& gt;V& gt;Mn \] Thus \[ D\rightarrow I \] Final matching: \[ A\rightarrow III \] \[ B\rightarrow IV \] \[ C\rightarrow II \] \[ D\rightarrow I \] Thus answer becomes \[ \boxed{D} \]
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