Question:

Which of the following will give maximum number of isomers?

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SCN\(^-\) can coordinate through S or N atom, producing linkage isomerism.
Updated On: Jun 18, 2026
  • \([Co(NH_3)_4Cl_2]^+\)
  • \([Ni(en)(NH_3)_4]^{2+}\)
  • \([Ni(C_2O_4)(en)_2]\)
  • \([Cr(SCN)_2(NH_3)_4]^+\)
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The Correct Option is D

Solution and Explanation

Concept: Coordination compounds may show geometrical, optical and linkage isomerism.

Step 1:
Analyze each complex.
(A) \([Co(NH_3)_4Cl_2]^+\) shows cis-trans isomerism only. Number of isomers \(=2\). (B) \([Ni(en)(NH_3)_4]^{2+}\) shows geometrical isomerism. Number of isomers \(=2\). (C) \([Ni(C_2O_4)(en)_2]\) shows geometrical as well as optical isomerism. Total isomers \(=3\). (D) \([Cr(SCN)_2(NH_3)_4]^+\) SCN\(^-\) is an ambidentate ligand. It shows: \[ \text{Linkage isomerism} \] and \[ \text{Geometrical isomerism} \] Hence maximum number of isomers are obtained. \[ \boxed{[Cr(SCN)_2(NH_3)_4]^+} \]
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