Question:

Match the following:

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Classify hydrides based on electron count around central atom: electron precise (octet satisfied), electron deficient (less than octet), electron rich (lone pairs), and saline (ionic character).
Updated On: Jun 26, 2026
  • A – (ii), B – (iii), C – (i), D – (iv)
  • A – (i), B – (iii), C – (iv), D – (ii)
  • A – (iv), B – (ii), C – (iii), D – (i)
  • A – (ii), B – (i), C – (iv), D – (iii)
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The Correct Option is B

Solution and Explanation

Step 1: Identify type of hydride for each compound.
- SiH\(_4\) is electron precise (octet satisfied) → A – (i)
- H\(_2\)O is electron rich (lone pairs on oxygen) → D – (ii)
- MgH\(_2\) is electron deficient (less than octet) → C – (iii)
- B\(_2\)H\(_6\) is electron deficient (3-center 2-electron bonds) → C – (iv)

Step 2: Match hydride types with examples.
From Step 1, the correct matches are:
A – SiH\(_4\) (i), B – H\(_2\)O (ii), C – MgH\(_2\) (iii), D – B\(_2\)H\(_6\) (iv)

Step 3: Conclusion.
\[ \boxed{\text{A – (i), B – (iii), C – (iv), D – (ii)}} \]
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