Match List I with List IILIST I (Amines) LIST II (pKb) A Aniline I 3.25 B Ethanamine II 3.00 C N-Ethylethanamine III 9.38 D N, N-Diethylethanamine IV 3.29
Choose the correct answer from the options given below:
| LIST I (Amines) | LIST II (pKb) | ||
| A | Aniline | I | 3.25 |
| B | Ethanamine | II | 3.00 |
| C | N-Ethylethanamine | III | 9.38 |
| D | N, N-Diethylethanamine | IV | 3.29 |
- A-III, B-IV, C-II, D-I
- A-III, B-II, C-IV, D-I
- A-I, B-IV, C-II, D-III
- A-III, B-II, C-I, D-IV
The Correct Option is A
Approach Solution - 1
The correct answer is (A) : A-III, B-IV, C-II, D-I
Amines are organic compounds that contain a nitrogen atom bonded to one or more alkyl or aryl groups. They are weak bases and react with acids to form salts.
The strength of a base is measured by its pKb value, which is the negative logarithm of its base dissociation constant (Kb). The higher the pKb value, the weaker the base.
List I contains the names of different amines, while List II contains their respective pKb values.
To match the amines with their correct pKb values, we need to compare their structures and the effects of the different alkyl or aryl groups attached to the nitrogen atom on their basicity.
Approach Solution -2
and List II contains four pKb values (3.25, 3.00, 9.38, and 3.29).
The task is to match each amine in List I with its corresponding pKb value in List II.
The correct matching is as follows:
Aniline (A) corresponds to 9.38 (III),
Ethylamine (B) corresponds to 3.29 (IV),
N-Ethylethanamine (C) corresponds to 3.00 (II),
and N,N-Diethylethanamine (D) corresponds to 3.25 (I).
This matching indicates the basicity of the amines, where lower pKb values signify stronger bases.
The correct answer, therefore, is option (4): A-III, B-IV, C-II, D-I.
Top Questions on Amines
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(ii) How is a primary amine distinguished from a secondary amine using the Hinsberg test? - Write the structures of (A), (B), and (C) in the following reaction:
\[ C_6H_5NO_2 \xrightarrow{Fe/HCl} (A) \xrightarrow[\text{273 K}]{NaNO_2 + HCl} (B) \xrightarrow[\Delta]{H_2O/H^+} (C) \] - What happens when aniline reacts with the following:
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(C) $HNO_2 + HCl (0^\circ - 5^\circ C)$ - Why is \(-NH_2\) group of aniline acetylated before carrying out nitration?
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Concepts Used:
Amines
Amine is a type of compound which is derived from ammonia (NH3). According to Organic chemistry, they are basically classified as the functional groups of the organic nitrogen compounds that contain nitrogen atoms with a lone pair.
Amine - Types
Primary Amines:
It is formed when one hydrogen atom in ammonia is substituted by an alkyl or aromatic group. Amino acids and methyl amine are the best examples that why aromatic amines include aniline.
Secondary Amines:
Amines that have two organic substitutes either alkyl or aryl ones or both and are bound to the nitrogen together with one hydrogen are termed as secondary amines. For Example, Dimethylamine.
Tertiary Amines:
Tertiary Amines are the amines where the nitrogen consists of three organic substitutes. For example, Trimethylamine and EDTA.