Question:

Match List - I with List - II. List - I
A. The value arrived at by dividing the sum of observations by total observation
B. The item which occurs more frequently
C. The middle most item
D. Is the reciprocal of the mean of the reciprocal of the values
List - II
I. Mode
II. Mean
III. Harmonic mean
IV. Median

Show Hint

Mean = average
Median = middle value
Mode = most frequent
Updated On: May 15, 2026
  • A-IV, B-II, C-I, D-III
  • A-II, B-I, C-IV, D-III
  • A-I, B-III, C-II, D-IV
  • A-III, B-IV, C-I, D-II
Show Solution
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The Correct Option is B

Solution and Explanation

Concept:
Measures of central tendency are used in statistics to summarize data.

Step 1: Mean (A)


• Defined as: \[ \text{Mean} = \frac{\text{Sum of observations}}{\text{Number of observations}} \] Thus, A $\rightarrow$ II.

Step 2: Mode (B)


• Value that occurs most frequently in a dataset. Thus, B $\rightarrow$ I.

Step 3: Median (C)


• Middle value when data is arranged in order. Thus, C $\rightarrow$ IV.

Step 4: Harmonic Mean (D)


• Defined as reciprocal of the arithmetic mean of reciprocals. \[ HM = \frac{n}{\sum \frac{1}{x_i}} \] Thus, D $\rightarrow$ III. Final Matching: \[ A-II,\; B-I,\; C-IV,\; D-III \] \[ \boxed{\text{Option (B)}} \]
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