Question

Match List-I with List-II.

List - I		List - II
A.	Bragg's Law	I.	\[ \frac{K}{\sigma}=LT \]
B.	Dulong-Petit's Law	II.	\[ n\lambda=2d\sin\theta \]
C.	Wiedemann-Franz Law	III.	\[ C_V=3R \]
D.	Curie-Weiss Law	IV.	\[ \chi=\frac{C}{T-\theta} \]

• A. A-II, B-III, C-I, D-IV
• B. A-I, B-II, C-III, D-IV
• C. A-IV, B-III, C-II, D-I
• D. A-III, B-IV, C-I, D-II

Hint:

Remember: Bragg's law is \(n\lambda=2d\sin\theta\), and Dulong-Petit's law is \(C_V=3R\).

Answer 1

The Correct Option is A

Concept:
This question is based on important laws used in solid state physics and material science.

Step 1: Bragg's law.
Bragg's law for X-ray diffraction is: \[ n\lambda=2d\sin\theta \] So, \[ A\rightarrow II \]

Step 2: Dulong-Petit's law.
Dulong-Petit's law gives molar specific heat of solids at high temperature: \[ C_V=3R \] So, \[ B\rightarrow III \]

Step 3: Wiedemann-Franz law.
Wiedemann-Franz law relates thermal and electrical conductivities: \[ \frac{K}{\sigma}=LT \] So, \[ C\rightarrow I \]

Step 4: Curie-Weiss law.
Curie-Weiss law is: \[ \chi=\frac{C}{T-\theta} \] So, \[ D\rightarrow IV \] Therefore: \[ A-II,\ B-III,\ C-I,\ D-IV \] \[ \therefore \text{Correct Answer is (A)} \]