Question

Match List-I with List-II. 

List-I (Electrical Properties)	List-II (Thermal Equivalent Properties)
(A) Voltage (V)	(I) Heat (Q)
(B) Resistance (Re)	(II) Heat flow (q)
(C) Current (i)	(III) Resistance \(\left(\frac{1}{AK}\right)\)
(D) Charge (Q)	(IV) Temperature (t)

Choose the correct answer from the options given below.

• (A) - (IV), (B) - (III), (C) - (II), (D) - (I)
• (A) - (II), (B) - (III), (C) - (I), (D) - (IV)
• (A) - (I), (B) - (II), (C) - (IV), (D) - (III)
• (A) - (I), (B) - (IV), (C) - (II), (D) - (III)

Answer 1

The Correct Option is A

Step 1: Understanding the Concept:
The electrical-thermal analogy compares heat transfer through a medium to the flow of electrical current through a conductor.

Step 2: Detailed Explanation:
Under Ohm's law and Fourier's law of heat conduction:
- Voltage (\(V\)), the electrical driving force, is analogous to Temperature (\(t\)), the thermal driving force (A - IV).
- Electrical Resistance (\(R_e\)) is analogous to Thermal Resistance (\(R_{th} = \frac{1}{AK}\)), which restricts the flow of energy (B - III).
- Electrical Current (\(i\)), the rate of charge flow, is analogous to Heat Flow Rate (\(q\)), the rate of thermal energy transfer (C - II).
- Electrical Charge (\(Q\)) is analogous to Heat quantity (\(Q\)) (D - I).

Step 3: Final Answer:
Matching the pairs gives (A)-(IV), (B)-(III), (C)-(II), (D)-(I), which is Option (A).