Question

Match List-I with List-II. 

List-I (Electrical Properties)	List-II (Thermal Equivalent)
(A) Voltage (V)	(I) Heat (Q)
(B) Resistance (Re)	(II) Heat flow (q)
(C) Current (i)	(III) Resistance \(\left(\frac{1}{AK}\right)\)
(D) Charge (Q)	(IV) Temperature (t)

Choose the correct answer from the options given below.

• (A) - (IV), (B) - (III), (C) - (II), (D) - (I)
• (A) - (II), (B) - (III), (C) - (I), (D) - (IV)
• (A) - (I), (B) - (II), (C) - (IV), (D) - (III)
• (A) - (I), (B) - (IV), (C) - (II), (D) - (III)

Hint:

Remember: Temperature difference (\(\Delta T\)) drives heat flow, just as Voltage difference (\(\Delta V\)) drives electric current flow.

Answer 1

The Correct Option is A

Step 1: Understanding the Concept:
Heat transfer by conduction is mathematically analogous to the flow of electricity, allowing thermal systems to be modeled using electrical circuit principles.

Step 2: Detailed Explanation:
The mathematical analogy between Ohm's Law (\(I = V/R\)) and Fourier's Law of Heat Conduction (\(q = \Delta T / R_{th}\)) establishes the following equivalent pairs:
- Voltage (V) (A) is the driving force in electrical systems, equivalent to Temperature (t) (IV), which is the driving force in thermal systems.
- Electrical Resistance (Re) (B) resists current flow, equivalent to Thermal Resistance (\(1/Ak\)) (III), which resists heat flow.
- Current (i) (C) is the rate of electrical charge flow, equivalent to Heat flow rate (q) (II).
- Electrical Charge (Q) (D) represents quantity of electricity, equivalent to Heat Quantity (Q) (I).
This matches up as: (A) - (IV), (B) - (III), (C) - (II), (D) - (I).

Step 3: Final Answer:
The correct matching corresponds to Option A.