Question

Match List-I with List-II: 

List-I		List-II
(A)	Malachite Green	(III)	Bacterial Endospore
(B)	Tannic Acid	(I)	Bacterial Flagella
(C)	Giemsa	(IV)	Malarial Parasite
(D)	Carbol Fuchsin	(II)	Mycobacterium tuberculosis

• A. \(A\text{-III},\ B\text{-I},\ C\text{-IV},\ D\text{-II}\)
• B. \(A\text{-II},\ B\text{-III},\ C\text{-I},\ D\text{-IV}\)
• C. \(A\text{-III},\ B\text{-II},\ C\text{-I},\ D\text{-IV}\)
• D. \(A\text{-IV},\ B\text{-III},\ C\text{-I},\ D\text{-II}\)

Hint:

Remember:
• Malachite green \(\rightarrow\) Endospore stain
• Tannic acid \(\rightarrow\) Flagella staining mordant
• Giemsa stain \(\rightarrow\) Malarial parasite
• Carbol fuchsin \(\rightarrow\) Acid-fast bacteria

Answer 1

The Correct Option is A

Concept: Different microbiological stains are used to identify specific cellular structures and microorganisms. Important stains include:
• Malachite green
• Tannic acid
• Giemsa stain
• Carbol fuchsin

Step 1: Matching Malachite green. Malachite green is used in: \[ \text{Endospore staining} \] especially in the Schaeffer-Fulton method. Thus: \[ A \rightarrow III \]

Step 2: Matching Tannic acid. Tannic acid acts as a mordant in: \[ \text{Flagella staining} \] helping increase flagellar thickness for visualization. Thus: \[ B \rightarrow I \]

Step 3: Matching Giemsa stain. Giemsa stain is commonly used for detecting: \[ \text{Malarial parasites} \] in blood smears. Thus: \[ C \rightarrow IV \]

Step 4: Matching Carbol fuchsin. Carbol fuchsin is the primary stain used in: \[ \text{Acid-fast staining} \] for identifying: \[ \textit{Mycobacterium tuberculosis} \] Thus: \[ D \rightarrow II \]

Step 5: Determining the correct combination. Therefore: \[ \boxed{ A\text{-III},\ B\text{-I},\ C\text{-IV},\ D\text{-II} } \] Hence, the correct answer is: \[ \boxed{(A)\ A\text{-III},\ B\text{-I},\ C\text{-IV},\ D\text{-II}} \]