Question:

Match List-I with List-II: 

List-I (Microbial Groups)List-II (Structural Organisation)
(A)Bacteria(III)Cellular, Prokaryotic
(B)Prions(I)Only Proteins
(C)Fungi(IV)Cellular, Eukaryotic
(D)Viroids(II)Nucleic Acid

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Remember:
• Bacteria \(\rightarrow\) Prokaryotic
• Fungi \(\rightarrow\) Eukaryotic
• Prions \(\rightarrow\) Infectious proteins only
• Viroids \(\rightarrow\) Naked RNA molecules
Updated On: Jun 7, 2026
  • \(A\text{-III},\ B\text{-II},\ C\text{-IV},\ D\text{-I}\)
  • \(A\text{-IV},\ B\text{-II},\ C\text{-III},\ D\text{-I}\)
  • \(A\text{-III},\ B\text{-I},\ C\text{-IV},\ D\text{-II}\)
  • \(A\text{-I},\ B\text{-II},\ C\text{-IV},\ D\text{-III}\)
Show Solution
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The Correct Option is C

Solution and Explanation

Concept: Microorganisms differ in their structural organization and biological nature. They may be:
• Prokaryotic
• Eukaryotic
• Proteinaceous infectious particles
• Naked nucleic acids

Step 1:
Matching Bacteria. Bacteria are: \[ \text{Cellular, prokaryotic organisms} \] Thus: \[ A \rightarrow III \]

Step 2:
Matching Prions. Prions are infectious particles composed of: \[ \text{Only proteins} \] They lack nucleic acids. Thus: \[ B \rightarrow I \]

Step 3:
Matching Fungi. Fungi are: \[ \text{Cellular, eukaryotic organisms} \] Thus: \[ C \rightarrow IV \]

Step 4:
Matching Viroids. Viroids consist only of: \[ \text{Small circular RNA molecules} \] Therefore, they are composed solely of: \[ \text{Nucleic acid} \] Thus: \[ D \rightarrow II \]

Step 5:
Determining the correct combination. Therefore: \[ \boxed{ A\text{-III},\ B\text{-I},\ C\text{-IV},\ D\text{-II} } \] Hence, the correct answer is: \[ \boxed{(C)\ A\text{-III},\ B\text{-I},\ C\text{-IV},\ D\text{-II}} \]
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