Question:
Match List I with List II:
Match List I with List II:
Show Hint
Equivalent weight of KMnO\(_4\) changes with medium because n-factor changes in different redox conditions.
Updated On: Jul 18, 2026
- A → i; B → ii; C → iii
- A → ii; B → iii; C → i
- A → i; B → iii; C → ii
- A → iii; B → ii; C → i
Show Solution
Verified By Collegedunia
The Correct Option is B
Solution and Explanation
Step 1: Understand equivalent weight concept of KMnO\(_4\).
The equivalent weight of KMnO\(_4\) depends on the number of electrons exchanged in redox reaction, which changes with the reaction medium. Hence, the same compound has different equivalent weights in acidic, neutral, and basic media.
Step 2: Determine oxidation states and reduction behavior.
In acidic medium, MnO\(_4^-\) reduces to Mn\(^{2+}\) (gain of 5 electrons). In neutral medium, it reduces to MnO\(_2\) (gain of 3 electrons). In strongly basic medium, it reduces to MnO\(_4^{2-}\) (gain of 1 electron).
Step 3: Compute equivalent weight formula basis.
Equivalent weight is given by: \[ \text{Eq. wt.} = \frac{Molecular\ weight}{n\text{-factor}} \] Molecular weight of KMnO\(_4\) = 158.
Step 4: Calculate values in each medium.
Acidic medium: \(n = 5\), so \[ \frac{158}{5} = 31.6 \] Neutral medium: \(n = 3\), so \[ \frac{158}{3} \approx 52.7 \] Basic medium: \(n = 1\), so \[ \frac{158}{1} = 158 \]
Step 5: Match with given list.
So, A (acidic) → 31.6 → (ii) B (neutral) → 52.7 → (iii) C (basic) → 158 → (i)
Step 6: Final conclusion.
Thus, correct matching is: \[ A \to ii,\; B \to iii,\; C \to i \] \[ \boxed{(2)} \]
The equivalent weight of KMnO\(_4\) depends on the number of electrons exchanged in redox reaction, which changes with the reaction medium. Hence, the same compound has different equivalent weights in acidic, neutral, and basic media.
Step 2: Determine oxidation states and reduction behavior.
In acidic medium, MnO\(_4^-\) reduces to Mn\(^{2+}\) (gain of 5 electrons). In neutral medium, it reduces to MnO\(_2\) (gain of 3 electrons). In strongly basic medium, it reduces to MnO\(_4^{2-}\) (gain of 1 electron).
Step 3: Compute equivalent weight formula basis.
Equivalent weight is given by: \[ \text{Eq. wt.} = \frac{Molecular\ weight}{n\text{-factor}} \] Molecular weight of KMnO\(_4\) = 158.
Step 4: Calculate values in each medium.
Acidic medium: \(n = 5\), so \[ \frac{158}{5} = 31.6 \] Neutral medium: \(n = 3\), so \[ \frac{158}{3} \approx 52.7 \] Basic medium: \(n = 1\), so \[ \frac{158}{1} = 158 \]
Step 5: Match with given list.
So, A (acidic) → 31.6 → (ii) B (neutral) → 52.7 → (iii) C (basic) → 158 → (i)
Step 6: Final conclusion.
Thus, correct matching is: \[ A \to ii,\; B \to iii,\; C \to i \] \[ \boxed{(2)} \]
Was this answer helpful?
0
0
Top AP EAPCET Chemistry Questions
- The four quantum numbers of the valence electron of potassium are :
- The volume of $0.02\, M$ acidified permanganate solution required for complete reaction of $60\, mL$ of $0.01\, MI^{-}$ ion solution to form $I_2$ in $mL$ is
- In which of the following the election gain enthalpy of elements is correctly arranged?
- The radii of $ \text{F,}{{\text{F}}^{-}}\text{O} $ and $ {{\text{O}}^{2-}} $ are in the order
- Which of the following has the highest first ionization potential?
View More Questions
Top AP EAPCET Redox reactions Questions
- Which of the following occurs with KMnO\(_4\) in neutral medium?
Given below are two statements: Statement-I: In the decomposition of potassium chlorate, Cl is reduced.
Statement-II: Reaction of Na with \( O_2 \) to form \( Na_2O \) is a redox reaction.- In aqueous solutions, the strongest reducing agents in Group 1 and Group 2 elements of the periodic table respectively are
- In which of the following reactions is ${H_2O}$ oxidized?
I. Photosynthesis
II. ${H_2O + F_2}$
III. ${H_2O + H_2}$
IV. ${H_2O + P_4O_{10}}$ - What are the oxidation states of the three Br atoms in the molecule \( \mathrm{Br_3O_6} \)?
View More Questions
Top AP EAPCET Questions
- A body is projected from the ground at an angle of $\tan^{-1} \left( \frac{8}{7}\right)$ with the horizontal. The ratio of the maximum height attained by it to its range is
- The four quantum numbers of the valence electron of potassium are :
- A lens forms real and virtual images of an object, when the object is at $u_{1}$ and $u_{2}$ distances respectively. If the size of the virtual image is double that of the real image, then the focal length of the lens is (take, the magnification of the real image as $m$ )
- Two spheres $P$ and $Q$, each of mass $200\, g$ are attached to a string of length one metre as shown in the figure. The string and the spheres are then whirled in a horizontal circle about $O$ at a constant angular speed. The ratio of the tension in the string between $P$ and $Q$ to that of between $P$ and $O$ is $(P$ is at mid-point of the line joining $O$ and $Q$ )
- The volume of $0.02\, M$ acidified permanganate solution required for complete reaction of $60\, mL$ of $0.01\, MI^{-}$ ion solution to form $I_2$ in $mL$ is
View More Questions