Question:

Match List-I (Time domain function) with List-II (Laplace transform).

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Delay → multiply by $e^{-as}$ in Laplace.
Updated On: May 20, 2026
  • A-I, B-II, C-III, D-IV
  • A-I, B-IV, C-III, D-II
  • A-IV, B-III, C-I, D-II
  • A-IV, B-III, C-II, D-I
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The Correct Option is C

Solution and Explanation

Concept: Standard Laplace transforms:

Step 1: $\sin(\omega t)u(t)$
\[ \frac{\omega}{s^2 + \omega^2} \Rightarrow A \rightarrow IV \]

Step 2: Delayed sine
\[ \sin\omega(t-a)u(t-a) \rightarrow e^{-as}\frac{\omega}{s^2+\omega^2} \Rightarrow B \rightarrow III \]

Step 3: Exponential sine
\[ e^{-at}\sin\omega t \rightarrow \frac{\omega}{(s+a)^2+\omega^2} \Rightarrow C \rightarrow I \]

Step 4: Delayed exponential sine
\[ \Rightarrow D \rightarrow II \] \[ \therefore \text{Correct answer is (C)} \]
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