Question:

$\lim_{x\to 0} \frac{\sin x - \sin x}{x^3}$ is

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If numerator is identically zero, limit is zero.
Updated On: Apr 8, 2026
  • $-2$
  • $2$
  • $0$
  • None of these
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The Correct Option is D

Solution and Explanation

Step 1: $\sin x - \sin x = 0$. So numerator is 0.}
Step 2: $\lim_{x\to 0} \frac{0}{x^3} = 0$.}
Step 3: But $0$ is not in options? Actually option (C) is $0$. So answer is (C).}
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